Do we need to know this for the test, and if so can you briefly go over it and how to do it?

Static equilibrium is a fancy way of saying that there is zero net force, zero net torque, and itâ€™s not moving. So yep, itâ€™s fair game for the test.

Any time you have done a â€śsum of the forcesâ€ť or â€śsum of the torquesâ€ť problem, and you set it equal to zero, youâ€™ve done a static equilibrium problem.

ah that makes sense, i just havent done much with torque T~T

Good news, if you are A-ok at summing forces, itâ€™s basically exactly the same for torque!

For Newtonâ€™s 2nd law, \sum F = ma, there is the rotational equivalent, \sum \tau = I\alpha. Where forces are either + or - for right or left, torques are + or - for clockwise or counterclockwise. Itâ€™s a little trickier because you have to actually calculate the torques, but if you remember that \tau = R \times F youâ€™ll be A-ok!

that makes sense, thank you!